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(4x=2)(6x^2-x+2)
We move all terms to the left:
(4x-(2)(6x^2-x+2))=0
We calculate terms in parentheses: +(4x-2(6x^2-x+2)), so:We get rid of parentheses
4x-2(6x^2-x+2)
We multiply parentheses
-12x^2+4x+2x-4
We add all the numbers together, and all the variables
-12x^2+6x-4
Back to the equation:
+(-12x^2+6x-4)
-12x^2+6x-4=0
a = -12; b = 6; c = -4;
Δ = b2-4ac
Δ = 62-4·(-12)·(-4)
Δ = -156
Delta is less than zero, so there is no solution for the equation
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